Text Box: Text Box: PROBLEM: find solution for equation -4(x-2)(x+3)-5x2-4=-5x(2x-3)+5x2-3 Text Box: Find a variable in the equation:
x is the variable
-4(x-2)(x+3)-5x2-4=-5x(2x-3)+5x2-3 is the equation with one variable x
Find a variable with an exponent:
-4(x-2)(x+3)-5x2-4=-5x(2x-3)+5x2-3 can be quadratic equation (it has exponent x2) Text Box: Find expression on the left side and on the right side of the equation:
expression on the left side of equation is -4(x-2)(x+3)-5x2-4
expression on the right side of equation is -5x(2x-3)+5x2-3 Text Box: Equation is not in the proper form because right side -5x(2x-3)+5x2-3
is not equal to zero. Text Box: Perform operation on both sides of equation
The left side -4(x-2)(x+3)-5x2-4 and the right side -5x(2x-3)+5x2-3

The left side -4(x-2)(x+3)-5x2-4 and the right side -5x(2x-3)+5x2-3 Text Box: Equation -9x2-4x+20=-5x2+15x-3 is not in a proper form:
the right side =-5x2+15x-3 is not equal to zero Text Box: Find if equation -9x2-4x+20=-5x2+15x-3 is in a proper form Text Box: The result of performing operation on both sides of equation is as follows:
-9x2-4x+20=-5x2+15x-3 Text Box: Transform the equation -9x2-4x+20=-5x2+15x-3 into a proper form Text Box: As a result of transforming of the equation the following equation is obtained
-4x2-19x+23=0 Text Box: Find if equation -4x2-19x+23=0 is in a proper form Text Box: The equation -4x2-19x+23=0 is in a proper form ax2+bx+c=0 Text Box: Find terms with coefficients a, b, c and substitute the values into the quadratic equation Text Box: The two solutions for the variable x are: x=-5.73 and x=1